rm_work: remove debugging statements

Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
(cherry picked from commit e7da9a3adc1ed430fff7afae4233e62313759b65)
Signed-off-by: Armin Kuster <akuster808@gmail.com>

diff --git a/meta/classes/rm_work.bbclass b/meta/classes/rm_work.bbclass
index 59180829abfa68c676270c13744b48780893c8af..31d99e4554a137bf51cf02f35f48cdfa1be829f8 100644 (file)
--- a/meta/classes/rm_work.bbclass
+++ b/meta/classes/rm_work.bbclass
@@ -183,8 +183,6 @@ python inject_rm_work() {
         # work in the recipe itself.
         # In practice, addtask() here merely updates the dependencies.
         bb.build.addtask('do_rm_work', 'do_build', ' '.join(deps), d)
-        if "initial" in pn:
-            bb.warn(pn + "2: " + " ".join(deps))
 
     # Always update do_build_without_rm_work dependencies.
     bb.build.addtask('do_build_without_rm_work', '', ' '.join(deps), d)