cve-check: allow comparison of Vendor as well as Product

Some product names are too vague to be searched without also matching the
vendor, for example Flex could be the parser compiler we ship, or Adobe Flex, or
Apache Flex, or IBM Flex.

If entries in CVE_PRODUCT contain a colon then split it as vendor:product to improve the search.

Also don't use .format() to construct SQL as that can lead to security
issues. Instead, use ? placeholders and lets sqlite3 handle the escaping.

Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

diff --git a/meta/classes/cve-check.bbclass b/meta/classes/cve-check.bbclass
index 2a1381604ad45804917ae5c975d2615f5005e668..e8668b25663ee161c8a18c654d450b12478044b4 100644 (file)
--- a/meta/classes/cve-check.bbclass
+++ b/meta/classes/cve-check.bbclass
@@ -190,12 +190,16 @@ def check_cves(d, patched_cves):
     import sqlite3
     db_file = d.getVar("CVE_CHECK_DB_FILE")
     conn = sqlite3.connect(db_file)
-    c = conn.cursor()
-
-    query = "SELECT * FROM PRODUCTS WHERE PRODUCT IS '{0}';"
 
     for product in products:
-        for row in c.execute(query.format(product, pv)):
+        c = conn.cursor()
+        if ":" in product:
+            vendor, product = product.split(":", 1)
+            c.execute("SELECT * FROM PRODUCTS WHERE PRODUCT IS ? AND VENDOR IS ?", (product, vendor))
+        else:
+            c.execute("SELECT * FROM PRODUCTS WHERE PRODUCT IS ?", (product,))
+
+        for row in c:
             cve = row[1]
             version_start = row[4]
             operator_start = row[5]